Base | Representation |
---|---|
bin | 1001100110101101101101… |
… | …11011000001111101111111 |
3 | 2202210012002021220122102200 |
4 | 10303112312323001331333 |
5 | 10232023133304403203 |
6 | 112531014155322543 |
7 | 4306654361210640 |
oct | 463266673017577 |
9 | 82705067818380 |
10 | 21121423122303 |
11 | 68035aa799989 |
12 | 2451581a50453 |
13 | ba298454ca2a |
14 | 5303d4a1b6c7 |
15 | 26963b4b39a3 |
hex | 1335b6ec1f7f |
21121423122303 has 48 divisors (see below), whose sum is σ = 34929871232256. Its totient is φ = 12047664009600.
The previous prime is 21121423122299. The next prime is 21121423122307. The reversal of 21121423122303 is 30322132412112.
21121423122303 is a `hidden beast` number, since 2 + 1 + 1 + 2 + 1 + 42 + 312 + 2 + 303 = 666.
It is an interprime number because it is at equal distance from previous prime (21121423122299) and next prime (21121423122307).
It is not a de Polignac number, because 21121423122303 - 22 = 21121423122299 is a prime.
It is a super-3 number, since 3×211214231223033 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21121423122307) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 514496128 + ... + 514537178.
It is an arithmetic number, because the mean of its divisors is an integer number (727705650672).
Almost surely, 221121423122303 is an apocalyptic number.
21121423122303 is a deficient number, since it is larger than the sum of its proper divisors (13808448109953).
21121423122303 is a wasteful number, since it uses less digits than its factorization.
21121423122303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55564 (or 55561 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 21121423122303 its reverse (30322132412112), we get a palindrome (51443555534415).
The spelling of 21121423122303 in words is "twenty-one trillion, one hundred twenty-one billion, four hundred twenty-three million, one hundred twenty-two thousand, three hundred three".
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