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2112143135321 is a prime number
BaseRepresentation
bin11110101111000101100…
…010101001001001011001
321110220210212221101022102
4132233011202221021121
5234101132120312241
64254145525333145
7305411606266322
oct36570542511131
97426725841272
102112143135321
1174483381120a
122a14205671b5
13124235a72a8b
147432a54b449
1539e1d30d39b
hex1ebc58a9259

2112143135321 has 2 divisors, whose sum is σ = 2112143135322. Its totient is φ = 2112143135320.

The previous prime is 2112143135309. The next prime is 2112143135351. The reversal of 2112143135321 is 1235313412112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1711023579721 + 401119555600 = 1308061^2 + 633340^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112143135321 - 218 = 2112142873177 is a prime.

It is a super-2 number, since 2×21121431353212 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2112143135351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056071567660 + 1056071567661.

It is an arithmetic number, because the mean of its divisors is an integer number (1056071567661).

Almost surely, 22112143135321 is an apocalyptic number.

It is an amenable number.

2112143135321 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112143135321 is an equidigital number, since it uses as much as digits as its factorization.

2112143135321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4320, while the sum is 29.

Adding to 2112143135321 its reverse (1235313412112), we get a palindrome (3347456547433).

The spelling of 2112143135321 in words is "two trillion, one hundred twelve billion, one hundred forty-three million, one hundred thirty-five thousand, three hundred twenty-one".