211214440141 has 4 divisors (see below), whose sum is σ = 211239935872. Its totient is φ = 211188944412.

The previous prime is 211214440123. The next prime is 211214440159. The reversal of 211214440141 is 141044412112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (211214440123) and next prime (211214440159).

It is a cyclic number.

It is not a de Polignac number, because 211214440141 - 2⁵ = 211214440109 is a prime.

It is a super-2 number, since 2×211214440141² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211214440441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12735435 + ... + 12752008.

It is an arithmetic number, because the mean of its divisors is an integer number (52809983968).

Almost surely, 2^211214440141 is an apocalyptic number.

It is an amenable number.

211214440141 is a deficient number, since it is larger than the sum of its proper divisors (25495731).

211214440141 is an equidigital number, since it uses as much as digits as its factorization.

211214440141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25495730.

The product of its (nonzero) digits is 1024, while the sum is 25.

Adding to 211214440141 its reverse (141044412112), we get a palindrome (352258852253).

The spelling of 211214440141 in words is "two hundred eleven billion, two hundred fourteen million, four hundred forty thousand, one hundred forty-one".