Base | Representation |
---|---|
bin | 1001100110101110110010… |
… | …10111111010101101010011 |
3 | 2202210020120120111222022212 |
4 | 10303113121113322231103 |
5 | 10232030324241320313 |
6 | 112531151404022335 |
7 | 4310004610131443 |
oct | 463273127725523 |
9 | 82706516458285 |
10 | 21122001120083 |
11 | 6803876a8a1a6 |
12 | 24517035319ab |
13 | ba2a47213a56 |
14 | 53044b6b8123 |
15 | 2696720d73a8 |
hex | 1335d95fab53 |
21122001120083 has 2 divisors, whose sum is σ = 21122001120084. Its totient is φ = 21122001120082.
The previous prime is 21122001120049. The next prime is 21122001120137. The reversal of 21122001120083 is 38002110022112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21122001120083 - 216 = 21122001054547 is a prime.
It is a super-2 number, since 2×211220011200832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21122001110083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561000560041 + 10561000560042.
It is an arithmetic number, because the mean of its divisors is an integer number (10561000560042).
Almost surely, 221122001120083 is an apocalyptic number.
21122001120083 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122001120083 is an equidigital number, since it uses as much as digits as its factorization.
21122001120083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 21122001120083 its reverse (38002110022112), we get a palindrome (59124111142195).
The spelling of 21122001120083 in words is "twenty-one trillion, one hundred twenty-two billion, one million, one hundred twenty thousand, eighty-three".
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