Base | Representation |
---|---|
bin | 10011101010111110… |
… | …000101000001101011 |
3 | 2000112000210100022201 |
4 | 103222332011001223 |
5 | 321224213324433 |
6 | 13411530001031 |
7 | 1345265063464 |
oct | 235276050153 |
9 | 60460710281 |
10 | 21122011243 |
11 | 8a59908743 |
12 | 4115876177 |
13 | 1cb7c94308 |
14 | 1045313d6b |
15 | 8394eda7d |
hex | 4eaf8506b |
21122011243 has 2 divisors, whose sum is σ = 21122011244. Its totient is φ = 21122011242.
The previous prime is 21122011217. The next prime is 21122011247. The reversal of 21122011243 is 34211022112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21122011243 - 225 = 21088456811 is a prime.
It is a super-2 number, since 2×211220112432 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21122011243.
It is not a weakly prime, because it can be changed into another prime (21122011247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561005621 + 10561005622.
It is an arithmetic number, because the mean of its divisors is an integer number (10561005622).
Almost surely, 221122011243 is an apocalyptic number.
21122011243 is a deficient number, since it is larger than the sum of its proper divisors (1).
21122011243 is an equidigital number, since it uses as much as digits as its factorization.
21122011243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 21122011243 its reverse (34211022112), we get a palindrome (55333033355).
The spelling of 21122011243 in words is "twenty-one billion, one hundred twenty-two million, eleven thousand, two hundred forty-three".
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