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211220132003100 = 22325211375471054171
BaseRepresentation
bin110000000001101010000100…
…111011111111110100011100
31000200212110002011111010211200
4300001222010323333310130
5210141112312243044400
62025121104501515500
762330102526614553
oct6001520473776434
91020773064433750
10211220132003100
1161334a56022350
121b833a62a12b90
1390b1c8584716c
143a23174cc4d9a
1519644c1310b00
hexc01a84effd1c

211220132003100 has 432 divisors, whose sum is σ = 743121735248256. Its totient is φ = 49729837248000.

The previous prime is 211220132003077. The next prime is 211220132003117. The reversal of 211220132003100 is 1300231022112.

211220132003100 is a `hidden beast` number, since 2 + 1 + 1 + 220 + 132 + 0 + 0 + 310 + 0 = 666.

211220132003100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×2112201320031002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 199839015 + ... + 200893185.

Almost surely, 2211220132003100 is an apocalyptic number.

211220132003100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211220132003100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (371560867624128).

211220132003100 is an abundant number, since it is smaller than the sum of its proper divisors (531901603245156).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211220132003100 is a wasteful number, since it uses less digits than its factorization.

211220132003100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1054786 (or 1054776 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 211220132003100 its reverse (1300231022112), we get a palindrome (212520363025212).

The spelling of 211220132003100 in words is "two hundred eleven trillion, two hundred twenty billion, one hundred thirty-two million, three thousand, one hundred".