Base | Representation |
---|---|
bin | 11110101111001001000… |
… | …011100100110101010011 |
3 | 21110220221222220002201022 |
4 | 132233021003210311103 |
5 | 234101242214200201 |
6 | 4254155433230055 |
7 | 305413223422211 |
oct | 36571103446523 |
9 | 7426858802638 |
10 | 2112202100051 |
11 | 74486402529a |
12 | 2a143826232b |
13 | 124245049754 |
14 | 743342d9cb1 |
15 | 39e235a941b |
hex | 1ebc90e4d53 |
2112202100051 has 2 divisors, whose sum is σ = 2112202100052. Its totient is φ = 2112202100050.
The previous prime is 2112202099981. The next prime is 2112202100087. The reversal of 2112202100051 is 1500012022112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112202100051 is a prime.
It is a super-2 number, since 2×21122021000512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2112202180051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056101050025 + 1056101050026.
It is an arithmetic number, because the mean of its divisors is an integer number (1056101050026).
Almost surely, 22112202100051 is an apocalyptic number.
2112202100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112202100051 is an equidigital number, since it uses as much as digits as its factorization.
2112202100051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 17.
Adding to 2112202100051 its reverse (1500012022112), we get a palindrome (3612214122163).
The spelling of 2112202100051 in words is "two trillion, one hundred twelve billion, two hundred two million, one hundred thousand, fifty-one".
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