Base | Representation |
---|---|
bin | 11110101111001001000… |
… | …011100111100111011011 |
3 | 21110220221222220200100112 |
4 | 132233021003213213123 |
5 | 234101242220031301 |
6 | 4254155433354535 |
7 | 305413223500355 |
oct | 36571103474733 |
9 | 7426858820315 |
10 | 2112202111451 |
11 | 744864032913 |
12 | 2a1438268a4b |
13 | 1242450519b3 |
14 | 743343000d5 |
15 | 39e235ac9bb |
hex | 1ebc90e79db |
2112202111451 has 2 divisors, whose sum is σ = 2112202111452. Its totient is φ = 2112202111450.
The previous prime is 2112202111421. The next prime is 2112202111457. The reversal of 2112202111451 is 1541112022112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112202111451 - 222 = 2112197917147 is a prime.
It is a super-2 number, since 2×21122021114512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2112202111457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056101055725 + 1056101055726.
It is an arithmetic number, because the mean of its divisors is an integer number (1056101055726).
Almost surely, 22112202111451 is an apocalyptic number.
2112202111451 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112202111451 is an equidigital number, since it uses as much as digits as its factorization.
2112202111451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 2112202111451 its reverse (1541112022112), we get a palindrome (3653314133563).
The spelling of 2112202111451 in words is "two trillion, one hundred twelve billion, two hundred two million, one hundred eleven thousand, four hundred fifty-one".
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