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21122102099993 is a prime number
BaseRepresentation
bin1001100110101110111110…
…11001001000000000011001
32202210020211121112021201112
410303113133121020000121
510232031031114144433
6112531205412230105
74310010244344506
oct463273731100031
982706747467645
1021122102099993
116803918a8a974
12245173130b335
13ba2a6210b58b
1453045ac824ad
1526967add2348
hex1335df648019

21122102099993 has 2 divisors, whose sum is σ = 21122102099994. Its totient is φ = 21122102099992.

The previous prime is 21122102099947. The next prime is 21122102100007. The reversal of 21122102099993 is 39999020122112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17883696703744 + 3238405396249 = 4228912^2 + 1799557^2 .

It is a cyclic number.

It is not a de Polignac number, because 21122102099993 - 26 = 21122102099929 is a prime.

It is a super-2 number, since 2×211221020999932 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (21122102093993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561051049996 + 10561051049997.

It is an arithmetic number, because the mean of its divisors is an integer number (10561051049997).

Almost surely, 221122102099993 is an apocalyptic number.

It is an amenable number.

21122102099993 is a deficient number, since it is larger than the sum of its proper divisors (1).

21122102099993 is an equidigital number, since it uses as much as digits as its factorization.

21122102099993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 314928, while the sum is 50.

The spelling of 21122102099993 in words is "twenty-one trillion, one hundred twenty-two billion, one hundred two million, ninety-nine thousand, nine hundred ninety-three".