Search a number
-
+
211221122103 = 3223469013567
BaseRepresentation
bin1100010010110111000…
…0101000110000110111
3202012012100210202020100
43010231300220300313
511430040101401403
6241011133405143
721155153625465
oct3045560506067
9665170722210
10211221122103
118163a8a9332
1234b296397b3
1316bc1cb7bb4
14a31a4b1835
1557636412a3
hex312dc28c37

211221122103 has 6 divisors (see below), whose sum is σ = 305097176384. Its totient is φ = 140814081396.

The previous prime is 211221122083. The next prime is 211221122107. The reversal of 211221122103 is 301221122112.

It is not a de Polignac number, because 211221122103 - 29 = 211221121591 is a prime.

It is a super-2 number, since 2×2112211221032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211221122107) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11734506775 + ... + 11734506792.

Almost surely, 2211221122103 is an apocalyptic number.

211221122103 is a deficient number, since it is larger than the sum of its proper divisors (93876054281).

211221122103 is a wasteful number, since it uses less digits than its factorization.

211221122103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23469013573 (or 23469013570 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 211221122103 its reverse (301221122112), we get a palindrome (512442244215).

Subtracting 211221122103 from its reverse (301221122112), we obtain a palindrome (90000000009).

The spelling of 211221122103 in words is "two hundred eleven billion, two hundred twenty-one million, one hundred twenty-two thousand, one hundred three".

Divisors: 1 3 9 23469013567 70407040701 211221122103