Base | Representation |
---|---|
bin | 110000000001101011000100… |
… | …101110100011010001011010 |
3 | 1000200212112211202021210121011 |
4 | 300001223010232203101122 |
5 | 210141122010232020442 |
6 | 2025121403012204134 |
7 | 62330141203405033 |
oct | 6001530456432132 |
9 | 1020775752253534 |
10 | 211221202220122 |
11 | 61335455145226 |
12 | 1b83410130964a |
13 | 90b20c649a883 |
14 | 3a232370ada8a |
15 | 1964535262117 |
hex | c01ac4ba345a |
211221202220122 has 16 divisors (see below), whose sum is σ = 319338760204800. Its totient is φ = 104778181516752.
The previous prime is 211221202220099. The next prime is 211221202220123. The reversal of 211221202220122 is 221022202122112.
It is a super-2 number, since 2×2112212022201222 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211221202220093 and 211221202220102.
It is not an unprimeable number, because it can be changed into a prime (211221202220123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 808043622 + ... + 808304977.
It is an arithmetic number, because the mean of its divisors is an integer number (19958672512800).
Almost surely, 2211221202220122 is an apocalyptic number.
211221202220122 is a deficient number, since it is larger than the sum of its proper divisors (108117557984678).
211221202220122 is a wasteful number, since it uses less digits than its factorization.
211221202220122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1616349117.
The product of its (nonzero) digits is 512, while the sum is 22.
Adding to 211221202220122 its reverse (221022202122112), we get a palindrome (432243404342234).
The spelling of 211221202220122 in words is "two hundred eleven trillion, two hundred twenty-one billion, two hundred two million, two hundred twenty thousand, one hundred twenty-two".
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