Base | Representation |
---|---|
bin | 110000000001101011000100… |
… | …101110100011010001011011 |
3 | 1000200212112211202021210121012 |
4 | 300001223010232203101123 |
5 | 210141122010232020443 |
6 | 2025121403012204135 |
7 | 62330141203405034 |
oct | 6001530456432133 |
9 | 1020775752253535 |
10 | 211221202220123 |
11 | 61335455145227 |
12 | 1b83410130964b |
13 | 90b20c649a884 |
14 | 3a232370ada8b |
15 | 1964535262118 |
hex | c01ac4ba345b |
211221202220123 has 2 divisors, whose sum is σ = 211221202220124. Its totient is φ = 211221202220122.
The previous prime is 211221202220099. The next prime is 211221202220159. The reversal of 211221202220123 is 321022202122112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211221202220123 is a prime.
It is a super-2 number, since 2×2112212022201232 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211221202220923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610601110061 + 105610601110062.
It is an arithmetic number, because the mean of its divisors is an integer number (105610601110062).
Almost surely, 2211221202220123 is an apocalyptic number.
211221202220123 is a deficient number, since it is larger than the sum of its proper divisors (1).
211221202220123 is an equidigital number, since it uses as much as digits as its factorization.
211221202220123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 211221202220123 its reverse (321022202122112), we get a palindrome (532243404342235).
The spelling of 211221202220123 in words is "two hundred eleven trillion, two hundred twenty-one billion, two hundred two million, two hundred twenty thousand, one hundred twenty-three".
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