Base | Representation |
---|---|
bin | 110000000001101011000101… |
… | …001100001110101010000010 |
3 | 1000200212112212021221001120212 |
4 | 300001223011030032222002 |
5 | 210141122014230000002 |
6 | 2025121403451034122 |
7 | 62330141326466636 |
oct | 6001530514165202 |
9 | 1020775767831525 |
10 | 211221210000002 |
11 | 61335459579384 |
12 | 1b834103a3b942 |
13 | 90b20c7c92a57 |
14 | 3a23238136dc6 |
15 | 1964535c9c352 |
hex | c01ac530ea82 |
211221210000002 has 4 divisors (see below), whose sum is σ = 316831815000006. Its totient is φ = 105610605000000.
The previous prime is 211221210000001. The next prime is 211221210000071. The reversal of 211221210000002 is 200000012122112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 109220077607281 + 102001132392721 = 10450841^2 + 10099561^2 .
It is a super-2 number, since 2×2112212100000022 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (211221210000001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52805302499999 + ... + 52805302500002.
Almost surely, 2211221210000002 is an apocalyptic number.
211221210000002 is a deficient number, since it is larger than the sum of its proper divisors (105610605000004).
211221210000002 is a wasteful number, since it uses less digits than its factorization.
211221210000002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 105610605000003.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 211221210000002 its reverse (200000012122112), we get a palindrome (411221222122114).
The spelling of 211221210000002 in words is "two hundred eleven trillion, two hundred twenty-one billion, two hundred ten million, two", and thus it is an aban number.
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