Base | Representation |
---|---|
bin | 110000000001101011000101… |
… | …011000000110101011111011 |
3 | 1000200212112212111210012221011 |
4 | 300001223011120012223323 |
5 | 210141122021024104313 |
6 | 2025121404041454351 |
7 | 62330141365113655 |
oct | 6001530530065373 |
9 | 1020775774705834 |
10 | 211221213113083 |
11 | 61335460305278 |
12 | 1b834104aa13b7 |
13 | 90b20c8812a04 |
14 | 3a232387076d5 |
15 | 19645361b493d |
hex | c01ac5606afb |
211221213113083 has 2 divisors, whose sum is σ = 211221213113084. Its totient is φ = 211221213113082.
The previous prime is 211221213113011. The next prime is 211221213113161. The reversal of 211221213113083 is 380311312122112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211221213113083 - 245 = 176036841024251 is a prime.
It is a super-2 number, since 2×2112212131130832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (211221213114083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105610606556541 + 105610606556542.
It is an arithmetic number, because the mean of its divisors is an integer number (105610606556542).
Almost surely, 2211221213113083 is an apocalyptic number.
211221213113083 is a deficient number, since it is larger than the sum of its proper divisors (1).
211221213113083 is an equidigital number, since it uses as much as digits as its factorization.
211221213113083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 31.
Adding to 211221213113083 its reverse (380311312122112), we get a palindrome (591532525235195).
The spelling of 211221213113083 in words is "two hundred eleven trillion, two hundred twenty-one billion, two hundred thirteen million, one hundred thirteen thousand, eighty-three".
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