21122143301133 has 48 divisors (see below), whose sum is σ = 36407359672320. Its totient is φ = 11537709571872.

The previous prime is 21122143301131. The next prime is 21122143301201. The reversal of 21122143301133 is 33110334122112.

21122143301133 is a `hidden beast` number, since 2 + 1 + 1 + 2 + 214 + 330 + 113 + 3 = 666.

It is not a de Polignac number, because 21122143301133 - 2¹ = 21122143301131 is a prime.

It is a super-2 number, since 2×21122143301133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21122143301097 and 21122143301106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21122143301131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2327941 + ... + 6903882.

It is an arithmetic number, because the mean of its divisors is an integer number (758486659840).

Almost surely, 2^{21122143301133} is an apocalyptic number.

21122143301133 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

21122143301133 is a deficient number, since it is larger than the sum of its proper divisors (15285216371187).

21122143301133 is a wasteful number, since it uses less digits than its factorization.

21122143301133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9233438 (or 9233435 counting only the distinct ones).

The product of its (nonzero) digits is 2592, while the sum is 27.

Adding to 21122143301133 its reverse (33110334122112), we get a palindrome (54232477423245).

The spelling of 21122143301133 in words is "twenty-one trillion, one hundred twenty-two billion, one hundred forty-three million, three hundred one thousand, one hundred thirty-three".