Base | Representation |
---|---|
bin | 11110101111001010001… |
… | …000010001110010000001 |
3 | 21110221000020210002122201 |
4 | 132233022020101302001 |
5 | 234101311322004303 |
6 | 4254201315233201 |
7 | 305413532462212 |
oct | 36571210216201 |
9 | 7427006702581 |
10 | 2112220109953 |
11 | 744873206408 |
12 | 2a14422a8801 |
13 | 1242489b40b5 |
14 | 74336867409 |
15 | 39e24e6581d |
hex | 1ebca211c81 |
2112220109953 has 2 divisors, whose sum is σ = 2112220109954. Its totient is φ = 2112220109952.
The previous prime is 2112220109917. The next prime is 2112220110067. The reversal of 2112220109953 is 3599010222112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2112188435569 + 31674384 = 1453337^2 + 5628^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112220109953 - 229 = 2111683239041 is a prime.
It is a super-2 number, since 2×21122201099532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2112220107953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056110054976 + 1056110054977.
It is an arithmetic number, because the mean of its divisors is an integer number (1056110054977).
Almost surely, 22112220109953 is an apocalyptic number.
It is an amenable number.
2112220109953 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112220109953 is an equidigital number, since it uses as much as digits as its factorization.
2112220109953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 37.
The spelling of 2112220109953 in words is "two trillion, one hundred twelve billion, two hundred twenty million, one hundred nine thousand, nine hundred fifty-three".
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