Base | Representation |
---|---|
bin | 11110101111001010001… |
… | …001001010111011001011 |
3 | 21110221000021012222201112 |
4 | 132233022021022323023 |
5 | 234101311402002021 |
6 | 4254201324240535 |
7 | 305413534455461 |
oct | 36571211127313 |
9 | 7427007188645 |
10 | 2112220344011 |
11 | 744873356248 |
12 | 2a14423a014b |
13 | 124248a667ab |
14 | 743368c8831 |
15 | 39e24eaed5b |
hex | 1ebca24aecb |
2112220344011 has 2 divisors, whose sum is σ = 2112220344012. Its totient is φ = 2112220344010.
The previous prime is 2112220343969. The next prime is 2112220344041. The reversal of 2112220344011 is 1104430222112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112220344011 - 238 = 1837342437067 is a prime.
It is a super-2 number, since 2×21122203440112 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2112220344041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056110172005 + 1056110172006.
It is an arithmetic number, because the mean of its divisors is an integer number (1056110172006).
Almost surely, 22112220344011 is an apocalyptic number.
2112220344011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112220344011 is an equidigital number, since it uses as much as digits as its factorization.
2112220344011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 2112220344011 its reverse (1104430222112), we get a palindrome (3216650566123).
The spelling of 2112220344011 in words is "two trillion, one hundred twelve billion, two hundred twenty million, three hundred forty-four thousand, eleven".
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