Base | Representation |
---|---|
bin | 11110101111001010001… |
… | …111110111100111101011 |
3 | 21110221000101112012102012 |
4 | 132233022033313213223 |
5 | 234101312324144242 |
6 | 4254201430030135 |
7 | 305413555421021 |
oct | 36571217674753 |
9 | 7427011465365 |
10 | 2112222099947 |
11 | 744874345533 |
12 | 2a1442aa834b |
13 | 12424922cacb |
14 | 74336c24711 |
15 | 39e2520a282 |
hex | 1ebca3f79eb |
2112222099947 has 2 divisors, whose sum is σ = 2112222099948. Its totient is φ = 2112222099946.
The previous prime is 2112222099917. The next prime is 2112222100031. The reversal of 2112222099947 is 7499902222112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2112222099947 - 214 = 2112222083563 is a prime.
It is a super-2 number, since 2×21122220999472 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112222099895 and 2112222099904.
It is not a weakly prime, because it can be changed into another prime (2112222099917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056111049973 + 1056111049974.
It is an arithmetic number, because the mean of its divisors is an integer number (1056111049974).
Almost surely, 22112222099947 is an apocalyptic number.
2112222099947 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112222099947 is an equidigital number, since it uses as much as digits as its factorization.
2112222099947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 50.
The spelling of 2112222099947 in words is "two trillion, one hundred twelve billion, two hundred twenty-two million, ninety-nine thousand, nine hundred forty-seven".
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