211223100113 has 2 divisors, whose sum is σ = 211223100114. Its totient is φ = 211223100112.

The previous prime is 211223100107. The next prime is 211223100167. The reversal of 211223100113 is 311001322112.

211223100113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122295685264 + 88927414849 = 349708^2 + 298207^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211223100113 is a prime.

It is a super-2 number, since 2×211223100113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 211223100091 and 211223100100.

It is not a weakly prime, because it can be changed into another prime (211223100103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611550056 + 105611550057.

It is an arithmetic number, because the mean of its divisors is an integer number (105611550057).

Almost surely, 2^211223100113 is an apocalyptic number.

It is an amenable number.

211223100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211223100113 is an equidigital number, since it uses as much as digits as its factorization.

211223100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 211223100113 its reverse (311001322112), we get a palindrome (522224422225).

The spelling of 211223100113 in words is "two hundred eleven billion, two hundred twenty-three million, one hundred thousand, one hundred thirteen".