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2112231311041 is a prime number
BaseRepresentation
bin11110101111001010110…
…011000000011011000001
321110221001000212011122211
4132233022303000123001
5234101322203423131
64254202355302121
7305414026623355
oct36571263003301
97427030764584
102112231311041
11744879566a05
122a1445baa941
1312424b106567
1474338141465
1539e25e295b1
hex1ebcacc06c1

2112231311041 has 2 divisors, whose sum is σ = 2112231311042. Its totient is φ = 2112231311040.

The previous prime is 2112231311017. The next prime is 2112231311159. The reversal of 2112231311041 is 1401131322112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1340871361600 + 771359949441 = 1157960^2 + 878271^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112231311041 - 25 = 2112231311009 is a prime.

It is a super-2 number, since 2×21122313110412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2112231311341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056115655520 + 1056115655521.

It is an arithmetic number, because the mean of its divisors is an integer number (1056115655521).

Almost surely, 22112231311041 is an apocalyptic number.

It is an amenable number.

2112231311041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112231311041 is an equidigital number, since it uses as much as digits as its factorization.

2112231311041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 2112231311041 its reverse (1401131322112), we get a palindrome (3513362633153).

The spelling of 2112231311041 in words is "two trillion, one hundred twelve billion, two hundred thirty-one million, three hundred eleven thousand, forty-one".