Base | Representation |
---|---|
bin | 11110101111001010110… |
… | …011000000011100011011 |
3 | 21110221001000212011210011 |
4 | 132233022303000130123 |
5 | 234101322203424011 |
6 | 4254202355302351 |
7 | 305414026623544 |
oct | 36571263003433 |
9 | 7427030764704 |
10 | 2112231311131 |
11 | 744879566a87 |
12 | 2a1445baa9b7 |
13 | 12424b106606 |
14 | 743381414cb |
15 | 39e25e29621 |
hex | 1ebcacc071b |
2112231311131 has 4 divisors (see below), whose sum is σ = 2117248488064. Its totient is φ = 2107214134200.
The previous prime is 2112231311041. The next prime is 2112231311159. The reversal of 2112231311131 is 1311131322112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2112231311131 - 213 = 2112231302939 is a prime.
It is a super-2 number, since 2×21122313111312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2112231311231) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2508587835 + ... + 2508588676.
It is an arithmetic number, because the mean of its divisors is an integer number (529312122016).
Almost surely, 22112231311131 is an apocalyptic number.
2112231311131 is a deficient number, since it is larger than the sum of its proper divisors (5017176933).
2112231311131 is an equidigital number, since it uses as much as digits as its factorization.
2112231311131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5017176932.
The product of its digits is 216, while the sum is 22.
Adding to 2112231311131 its reverse (1311131322112), we get a palindrome (3423362633243).
The spelling of 2112231311131 in words is "two trillion, one hundred twelve billion, two hundred thirty-one million, three hundred eleven thousand, one hundred thirty-one".
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