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2112231311130 = 23570407710371
BaseRepresentation
bin11110101111001010110…
…011000000011100011010
321110221001000212011210010
4132233022303000130122
5234101322203424010
64254202355302350
7305414026623543
oct36571263003432
97427030764703
102112231311130
11744879566a86
122a1445baa9b6
1312424b106605
14743381414ca
1539e25e29620
hex1ebcacc071a

2112231311130 has 16 divisors (see below), whose sum is σ = 5069355146784. Its totient is φ = 563261682960.

The previous prime is 2112231311041. The next prime is 2112231311159. The reversal of 2112231311130 is 311131322112.

It is a super-2 number, since 2×21122313111302 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112231311097 and 2112231311106.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35203855156 + ... + 35203855215.

It is an arithmetic number, because the mean of its divisors is an integer number (316834696674).

Almost surely, 22112231311130 is an apocalyptic number.

2112231311130 is an abundant number, since it is smaller than the sum of its proper divisors (2957123835654).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2112231311130 is a wasteful number, since it uses less digits than its factorization.

2112231311130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70407710381.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2112231311130 its reverse (311131322112), we get a palindrome (2423362633242).

The spelling of 2112231311130 in words is "two trillion, one hundred twelve billion, two hundred thirty-one million, three hundred eleven thousand, one hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 70407710371 140815420742 211223131113 352038551855 422446262226 704077103710 1056115655565 2112231311130