Base | Representation |
---|---|
bin | 11110101111001010110… |
… | …110111001101011110001 |
3 | 21110221001002210001011202 |
4 | 132233022312321223301 |
5 | 234101322434111032 |
6 | 4254202433220545 |
7 | 305414041405103 |
oct | 36571266715361 |
9 | 7427032701152 |
10 | 2112232332017 |
11 | 74487a0a3a95 |
12 | 2a1446401755 |
13 | 12424b3a31a2 |
14 | 74338329573 |
15 | 39e2607bd62 |
hex | 1ebcadb9af1 |
2112232332017 has 2 divisors, whose sum is σ = 2112232332018. Its totient is φ = 2112232332016.
The previous prime is 2112232331969. The next prime is 2112232332083. The reversal of 2112232332017 is 7102332322112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1955757498256 + 156474833761 = 1398484^2 + 395569^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112232332017 - 210 = 2112232330993 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112232338017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056116166008 + 1056116166009.
It is an arithmetic number, because the mean of its divisors is an integer number (1056116166009).
Almost surely, 22112232332017 is an apocalyptic number.
It is an amenable number.
2112232332017 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112232332017 is an equidigital number, since it uses as much as digits as its factorization.
2112232332017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 29.
Adding to 2112232332017 its reverse (7102332322112), we get a palindrome (9214564654129).
The spelling of 2112232332017 in words is "two trillion, one hundred twelve billion, two hundred thirty-two million, three hundred thirty-two thousand, seventeen".
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