Base | Representation |
---|---|
bin | 110000000001101101000011… |
… | …000001100001100100100011 |
3 | 1000200212202022102101020001111 |
4 | 300001231003001201210203 |
5 | 210141140330201414412 |
6 | 2025122353143444151 |
7 | 62330244542651536 |
oct | 6001550301414443 |
9 | 1020782272336044 |
10 | 211223321123107 |
11 | 61336342214417 |
12 | 1b8345b2a56657 |
13 | 90b2373476717 |
14 | 3a2339867aa1d |
15 | 196460b2b02a7 |
hex | c01b43061923 |
211223321123107 has 2 divisors, whose sum is σ = 211223321123108. Its totient is φ = 211223321123106.
The previous prime is 211223321123093. The next prime is 211223321123147. The reversal of 211223321123107 is 701321123322112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211223321123107 is a prime.
It is not a weakly prime, because it can be changed into another prime (211223321123147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105611660561553 + 105611660561554.
It is an arithmetic number, because the mean of its divisors is an integer number (105611660561554).
Almost surely, 2211223321123107 is an apocalyptic number.
211223321123107 is a deficient number, since it is larger than the sum of its proper divisors (1).
211223321123107 is an equidigital number, since it uses as much as digits as its factorization.
211223321123107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 211223321123107 its reverse (701321123322112), we get a palindrome (912544444445219).
The spelling of 211223321123107 in words is "two hundred eleven trillion, two hundred twenty-three billion, three hundred twenty-one million, one hundred twenty-three thousand, one hundred seven".
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