211231014020021 has 4 divisors (see below), whose sum is σ = 215725290914112. Its totient is φ = 206736737125932.

The previous prime is 211231014020017. The next prime is 211231014020023. The reversal of 211231014020021 is 120020410132112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211231014020021 - 2² = 211231014020017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 211231014019975 and 211231014020002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211231014020023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2247138446975 + ... + 2247138447068.

It is an arithmetic number, because the mean of its divisors is an integer number (53931322728528).

Almost surely, 2^{211231014020021} is an apocalyptic number.

It is an amenable number.

211231014020021 is a deficient number, since it is larger than the sum of its proper divisors (4494276894091).

211231014020021 is an equidigital number, since it uses as much as digits as its factorization.

211231014020021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4494276894090.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 211231014020021 its reverse (120020410132112), we get a palindrome (331251424152133).

The spelling of 211231014020021 in words is "two hundred eleven trillion, two hundred thirty-one billion, fourteen million, twenty thousand, twenty-one".