Base | Representation |
---|---|
bin | 11110101111010000000… |
… | …111011100000101111111 |
3 | 21110221021020210011002021 |
4 | 132233100013130011333 |
5 | 234102013030201333 |
6 | 4254215304141011 |
7 | 305416162312120 |
oct | 36572007340577 |
9 | 7427236704067 |
10 | 2112320553343 |
11 | 74491497aa80 |
12 | 2a146ba67767 |
13 | 124263751660 |
14 | 74345d32047 |
15 | 39e2dba682d |
hex | 1ebd01dc17f |
2112320553343 has 128 divisors (see below), whose sum is σ = 2959428648960. Its totient is φ = 1455144238080.
The previous prime is 2112320553337. The next prime is 2112320553347. The reversal of 2112320553343 is 3433550232112.
It is a de Polignac number, because none of the positive numbers 2k-2112320553343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2112320553299 and 2112320553308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2112320553347) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 357835530 + ... + 357841432.
It is an arithmetic number, because the mean of its divisors is an integer number (23120536320).
Almost surely, 22112320553343 is an apocalyptic number.
2112320553343 is a deficient number, since it is larger than the sum of its proper divisors (847108095617).
2112320553343 is a wasteful number, since it uses less digits than its factorization.
2112320553343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6149.
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 2112320553343 its reverse (3433550232112), we get a palindrome (5545870785455).
The spelling of 2112320553343 in words is "two trillion, one hundred twelve billion, three hundred twenty million, five hundred fifty-three thousand, three hundred forty-three".
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