Base | Representation |
---|---|
bin | 1001100110110001001101… |
… | …10111110000011001100001 |
3 | 2202210100221012001120110122 |
4 | 10303120212313300121201 |
5 | 10232041010113441342 |
6 | 112531524411410025 |
7 | 4310052045441635 |
oct | 463304667603141 |
9 | 82710835046418 |
10 | 21123301312097 |
11 | 68043839a8756 |
12 | 2451a06a53915 |
13 | ba2bc36b823a |
14 | 530532248dc5 |
15 | 2696eb3144d2 |
hex | 133626df0661 |
21123301312097 has 2 divisors, whose sum is σ = 21123301312098. Its totient is φ = 21123301312096.
The previous prime is 21123301311961. The next prime is 21123301312111. The reversal of 21123301312097 is 79021310332112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21033514785361 + 89786526736 = 4586231^2 + 299644^2 .
It is a cyclic number.
It is not a de Polignac number, because 21123301312097 - 214 = 21123301295713 is a prime.
It is not a weakly prime, because it can be changed into another prime (21123301332097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561650656048 + 10561650656049.
It is an arithmetic number, because the mean of its divisors is an integer number (10561650656049).
Almost surely, 221123301312097 is an apocalyptic number.
It is an amenable number.
21123301312097 is a deficient number, since it is larger than the sum of its proper divisors (1).
21123301312097 is an equidigital number, since it uses as much as digits as its factorization.
21123301312097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 35.
The spelling of 21123301312097 in words is "twenty-one trillion, one hundred twenty-three billion, three hundred one million, three hundred twelve thousand, ninety-seven".
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