| Base | Representation |
|---|---|
| bin | 1001100110110001010001… |
| … | …10001011100010001000000 |
| 3 | 2202210101000102002012210220 |
| 4 | 10303120220301130101000 |
| 5 | 10232041041300224300 |
| 6 | 112531531511223040 |
| 7 | 4310052613540143 |
| oct | 463305061342100 |
| 9 | 82711012065726 |
| 10 | 21123333211200 |
| 11 | 680439aa05a50 |
| 12 | 2451a15677a80 |
| 13 | ba2bca1a674c |
| 14 | 53053659005a |
| 15 | 2696ee015da0 |
| hex | 133628c5c440 |
21123333211200 has 672 divisors, whose sum is σ = 78962094673920. Its totient is φ = 4897933516800.
The previous prime is 21123333211171. The next prime is 21123333211217. The reversal of 21123333211200 is 211233332112.
It is a super-3 number, since 3×211233332112003 (a number of 41 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 115170769 + ... + 115354031.
Almost surely, 221123333211200 is an apocalyptic number.
21123333211200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 21123333211200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (39481047336960).
21123333211200 is an abundant number, since it is smaller than the sum of its proper divisors (57838761462720).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21123333211200 is a wasteful number, since it uses less digits than its factorization.
21123333211200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183395 (or 183380 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 21123333211200 its reverse (211233332112), we get a palindrome (21334566543312).
21123333211200 divided by its reverse (211233332112) gives a square (100 = 102).
It can be divided in two parts, 211233 and 33211200, that added together give a palindrome (33422433).
The spelling of 21123333211200 in words is "twenty-one trillion, one hundred twenty-three billion, three hundred thirty-three million, two hundred eleven thousand, two hundred".
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