Base | Representation |
---|---|
bin | 1001100110110001011010… |
… | …11110011011011011110110 |
3 | 2202210101012220112211221001 |
4 | 10303120231132123123312 |
5 | 10232041222000110032 |
6 | 112531543410313514 |
7 | 4310054562311023 |
oct | 463305536333366 |
9 | 82711186484831 |
10 | 21123412113142 |
11 | 68044304a7169 |
12 | 2451a37b8889a |
13 | ba2c106410a1 |
14 | 530542c4c54a |
15 | 269705dee3e7 |
hex | 13362d79b6f6 |
21123412113142 has 4 divisors (see below), whose sum is σ = 31685118169716. Its totient is φ = 10561706056570.
The previous prime is 21123412113101. The next prime is 21123412113151. The reversal of 21123412113142 is 24131121432112.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×211234121131422 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 21123412113142.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5280853028284 + ... + 5280853028287.
It is an arithmetic number, because the mean of its divisors is an integer number (7921279542429).
Almost surely, 221123412113142 is an apocalyptic number.
21123412113142 is a deficient number, since it is larger than the sum of its proper divisors (10561706056574).
21123412113142 is a wasteful number, since it uses less digits than its factorization.
21123412113142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10561706056573.
The product of its digits is 2304, while the sum is 28.
Adding to 21123412113142 its reverse (24131121432112), we get a palindrome (45254533545254).
The spelling of 21123412113142 in words is "twenty-one trillion, one hundred twenty-three billion, four hundred twelve million, one hundred thirteen thousand, one hundred forty-two".
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