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21123412113142 = 210561706056571
BaseRepresentation
bin1001100110110001011010…
…11110011011011011110110
32202210101012220112211221001
410303120231132123123312
510232041222000110032
6112531543410313514
74310054562311023
oct463305536333366
982711186484831
1021123412113142
1168044304a7169
122451a37b8889a
13ba2c106410a1
14530542c4c54a
15269705dee3e7
hex13362d79b6f6

21123412113142 has 4 divisors (see below), whose sum is σ = 31685118169716. Its totient is φ = 10561706056570.

The previous prime is 21123412113101. The next prime is 21123412113151. The reversal of 21123412113142 is 24131121432112.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×211234121131422 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21123412113142.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5280853028284 + ... + 5280853028287.

It is an arithmetic number, because the mean of its divisors is an integer number (7921279542429).

Almost surely, 221123412113142 is an apocalyptic number.

21123412113142 is a deficient number, since it is larger than the sum of its proper divisors (10561706056574).

21123412113142 is a wasteful number, since it uses less digits than its factorization.

21123412113142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10561706056573.

The product of its digits is 2304, while the sum is 28.

Adding to 21123412113142 its reverse (24131121432112), we get a palindrome (45254533545254).

The spelling of 21123412113142 in words is "twenty-one trillion, one hundred twenty-three billion, four hundred twelve million, one hundred thirteen thousand, one hundred forty-two".

Divisors: 1 2 10561706056571 21123412113142