Base | Representation |
---|---|
bin | 1100010010111011110… |
… | …1000000011101100001 |
3 | 202012020202110212112012 |
4 | 3010232331000131201 |
5 | 11430110213021423 |
6 | 241013130442305 |
7 | 21155516040041 |
oct | 3045675003541 |
9 | 665222425465 |
10 | 211241142113 |
11 | 816501326a1 |
12 | 34b34293395 |
13 | 16bc61a7461 |
14 | a31d003721 |
15 | 5765298078 |
hex | 312ef40761 |
211241142113 has 2 divisors, whose sum is σ = 211241142114. Its totient is φ = 211241142112.
The previous prime is 211241142107. The next prime is 211241142179. The reversal of 211241142113 is 311241142112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114201415969 + 97039726144 = 337937^2 + 311512^2 .
It is a cyclic number.
It is not a de Polignac number, because 211241142113 - 24 = 211241142097 is a prime.
It is not a weakly prime, because it can be changed into another prime (211241042113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105620571056 + 105620571057.
It is an arithmetic number, because the mean of its divisors is an integer number (105620571057).
Almost surely, 2211241142113 is an apocalyptic number.
It is an amenable number.
211241142113 is a deficient number, since it is larger than the sum of its proper divisors (1).
211241142113 is an equidigital number, since it uses as much as digits as its factorization.
211241142113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 384, while the sum is 23.
Adding to 211241142113 its reverse (311241142112), we get a palindrome (522482284225).
Subtracting 211241142113 from its reverse (311241142112), we obtain a palindrome (99999999999).
The spelling of 211241142113 in words is "two hundred eleven billion, two hundred forty-one million, one hundred forty-two thousand, one hundred thirteen".
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