Base | Representation |
---|---|
bin | 1100010010111100000… |
… | …1011110000111000011 |
3 | 202012020211200022111012 |
4 | 3010233001132013003 |
5 | 11430111012442011 |
6 | 241013211511135 |
7 | 21155532012134 |
oct | 3045701360703 |
9 | 665224608435 |
10 | 211242312131 |
11 | 81650861754 |
12 | 34b347584ab |
13 | 16bc64c6b86 |
14 | a31d229c8b |
15 | 5765429a8b |
hex | 312f05e1c3 |
211242312131 has 2 divisors, whose sum is σ = 211242312132. Its totient is φ = 211242312130.
The previous prime is 211242312109. The next prime is 211242312139. The reversal of 211242312131 is 131213242112.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211242312131 is a prime.
It is a super-2 number, since 2×2112423121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211242312097 and 211242312106.
It is not a weakly prime, because it can be changed into another prime (211242312139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105621156065 + 105621156066.
It is an arithmetic number, because the mean of its divisors is an integer number (105621156066).
Almost surely, 2211242312131 is an apocalyptic number.
211242312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
211242312131 is an equidigital number, since it uses as much as digits as its factorization.
211242312131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576, while the sum is 23.
Adding to 211242312131 its reverse (131213242112), we get a palindrome (342455554243).
The spelling of 211242312131 in words is "two hundred eleven billion, two hundred forty-two million, three hundred twelve thousand, one hundred thirty-one".
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