Base | Representation |
---|---|
bin | 1100010010111100010… |
… | …1010010100100100100 |
3 | 202012020220120012000212 |
4 | 3010233011102210210 |
5 | 11430111242012234 |
6 | 241013245154552 |
7 | 21155543352332 |
oct | 3045705224444 |
9 | 665226505025 |
10 | 211243313444 |
11 | 81651385a89 |
12 | 34b34b5ba58 |
13 | 16bc6787877 |
14 | a31d40ab52 |
15 | 57655765ce |
hex | 312f152924 |
211243313444 has 12 divisors (see below), whose sum is σ = 369679026444. Its totient is φ = 105620734464.
The previous prime is 211243313443. The next prime is 211243313459. The reversal of 211243313444 is 444313342112.
It can be written as a sum of positive squares in 2 ways, for example, as 200983649344 + 10259664100 = 448312^2 + 101290^2 .
It is a super-2 number, since 2×2112433134442 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211243313444.
It is not an unprimeable number, because it can be changed into a prime (211243313441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 722864 + ... + 972120.
It is an arithmetic number, because the mean of its divisors is an integer number (30806585537).
Almost surely, 2211243313444 is an apocalyptic number.
It is an amenable number.
211243313444 is a deficient number, since it is larger than the sum of its proper divisors (158435713000).
211243313444 is a wasteful number, since it uses less digits than its factorization.
211243313444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 461134 (or 461132 counting only the distinct ones).
The product of its digits is 27648, while the sum is 32.
Adding to 211243313444 its reverse (444313342112), we get a palindrome (655556655556).
The spelling of 211243313444 in words is "two hundred eleven billion, two hundred forty-three million, three hundred thirteen thousand, four hundred forty-four".
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