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2112524052049 is a prime number
BaseRepresentation
bin11110101111011100001…
…111101110011001010001
321110221210102200221211101
4132233130033232121101
5234102422124131144
64254251413544401
7305424213110605
oct36573417563121
97427712627741
102112524052049
11744a09832624
122a1508045101
131242969622a8
1474364d85505
1539e419a26d4
hex1ebdc3ee651

2112524052049 has 2 divisors, whose sum is σ = 2112524052050. Its totient is φ = 2112524052048.

The previous prime is 2112524052007. The next prime is 2112524052071. The reversal of 2112524052049 is 9402504252112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1845880911424 + 266643140625 = 1358632^2 + 516375^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112524052049 is a prime.

It is a super-2 number, since 2×21125240520492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112524051999 and 2112524052017.

It is not a weakly prime, because it can be changed into another prime (2112524052349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056262026024 + 1056262026025.

It is an arithmetic number, because the mean of its divisors is an integer number (1056262026025).

Almost surely, 22112524052049 is an apocalyptic number.

It is an amenable number.

2112524052049 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112524052049 is an equidigital number, since it uses as much as digits as its factorization.

2112524052049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 37.

The spelling of 2112524052049 in words is "two trillion, one hundred twelve billion, five hundred twenty-four million, fifty-two thousand, forty-nine".