Base | Representation |
---|---|
bin | 11110101111011100001… |
… | …111101110011001110011 |
3 | 21110221210102200221212122 |
4 | 132233130033232121303 |
5 | 234102422124131313 |
6 | 4254251413544455 |
7 | 305424213110654 |
oct | 36573417563163 |
9 | 7427712627778 |
10 | 2112524052083 |
11 | 744a09832655 |
12 | 2a150804512b |
13 | 124296962303 |
14 | 74364d8552b |
15 | 39e419a2708 |
hex | 1ebdc3ee673 |
2112524052083 has 2 divisors, whose sum is σ = 2112524052084. Its totient is φ = 2112524052082.
The previous prime is 2112524052077. The next prime is 2112524052091. The reversal of 2112524052083 is 3802504252112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112524052083 is a prime.
It is not a weakly prime, because it can be changed into another prime (2112224052083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056262026041 + 1056262026042.
It is an arithmetic number, because the mean of its divisors is an integer number (1056262026042).
Almost surely, 22112524052083 is an apocalyptic number.
2112524052083 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112524052083 is an equidigital number, since it uses as much as digits as its factorization.
2112524052083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 38400, while the sum is 35.
The spelling of 2112524052083 in words is "two trillion, one hundred twelve billion, five hundred twenty-four million, fifty-two thousand, eighty-three".
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