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211253144103 = 32283308326903
BaseRepresentation
bin1100010010111110101…
…0110010101000100111
3202012021121001122011100
43010233222302220213
511430121301102403
6241014240011143
721156023045211
oct3045752625047
9665247048140
10211253144103
118165698a9a1
1234b38300ab3
1316bc881a321
14a3208495b1
1557663692a3
hex312fab2a27

211253144103 has 24 divisors (see below), whose sum is σ = 306332387712. Its totient is φ = 140287043088.

The previous prime is 211253144101. The next prime is 211253144147. The reversal of 211253144103 is 301441352112.

211253144103 is a `hidden beast` number, since 2 + 112 + 531 + 4 + 4 + 10 + 3 = 666.

It is not a de Polignac number, because 211253144103 - 21 = 211253144101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211253144101) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7838950 + ... + 7865852.

It is an arithmetic number, because the mean of its divisors is an integer number (12763849488).

Almost surely, 2211253144103 is an apocalyptic number.

211253144103 is a deficient number, since it is larger than the sum of its proper divisors (95079243609).

211253144103 is a wasteful number, since it uses less digits than its factorization.

211253144103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30275 (or 30272 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 27.

Adding to 211253144103 its reverse (301441352112), we get a palindrome (512694496215).

The spelling of 211253144103 in words is "two hundred eleven billion, two hundred fifty-three million, one hundred forty-four thousand, one hundred three".

Divisors: 1 3 9 283 849 2547 3083 9249 26903 27747 80709 242127 872489 2617467 7613549 7852401 22840647 68521941 82941949 248825847 746477541 23472571567 70417714701 211253144103