Base | Representation |
---|---|
bin | 110000000010001000111111… |
… | …111111011000010111101000 |
3 | 1000200222121210010210011201001 |
4 | 300002020333333120113220 |
5 | 210142133312230004202 |
6 | 2025144235313204344 |
7 | 62332356401466445 |
oct | 6002107777302750 |
9 | 1020877703704631 |
10 | 211253335000552 |
11 | 61348044276809 |
12 | 1b83a38a5606b4 |
13 | 90b514768a210 |
14 | 3a24a048989cc |
15 | 19652b622ad87 |
hex | c0223ffd85e8 |
211253335000552 has 32 divisors (see below), whose sum is σ = 426569837904000. Its totient is φ = 97501401226944.
The previous prime is 211253335000517. The next prime is 211253335000567. The reversal of 211253335000552 is 255000533352112.
211253335000552 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129166453 + ... + 130791739.
It is an arithmetic number, because the mean of its divisors is an integer number (13330307434500).
Almost surely, 2211253335000552 is an apocalyptic number.
It is an amenable number.
211253335000552 is an abundant number, since it is smaller than the sum of its proper divisors (215316502903448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
211253335000552 is a wasteful number, since it uses less digits than its factorization.
211253335000552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2875105 (or 2875101 counting only the distinct ones).
The product of its (nonzero) digits is 135000, while the sum is 37.
Adding to 211253335000552 its reverse (255000533352112), we get a palindrome (466253868352664).
The spelling of 211253335000552 in words is "two hundred eleven trillion, two hundred fifty-three billion, three hundred thirty-five million, five hundred fifty-two", and thus it is an aban number.
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