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2112543323503 = 31092175731231
BaseRepresentation
bin11110101111011101011…
…001001111010101101111
321110221211202222001021221
4132233131121033111233
5234102442042323003
64254253343004211
7305424535653604
oct36573531172557
97427752861257
102112543323503
11744a196a5548
122a1512599667
1312429a94bc12
14743677606ab
1539e4350c7bd
hex1ebdd64f56f

2112543323503 has 8 divisors (see below), whose sum is σ = 2113387612160. Its totient is φ = 2111699147040.

The previous prime is 2112543323447. The next prime is 2112543323521. The reversal of 2112543323503 is 3053233452112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112543323503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2112523323503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67626898 + ... + 67658128.

It is an arithmetic number, because the mean of its divisors is an integer number (264173451520).

Almost surely, 22112543323503 is an apocalyptic number.

2112543323503 is a deficient number, since it is larger than the sum of its proper divisors (844288657).

2112543323503 is a wasteful number, since it uses less digits than its factorization.

2112543323503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56097.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 2112543323503 its reverse (3053233452112), we get a palindrome (5165776775615).

The spelling of 2112543323503 in words is "two trillion, one hundred twelve billion, five hundred forty-three million, three hundred twenty-three thousand, five hundred three".

Divisors: 1 3109 21757 31231 67642513 97097179 679492867 2112543323503