Base | Representation |
---|---|
bin | 1100010010111111010… |
… | …0110011101010010001 |
3 | 202012021210000000212100 |
4 | 3010233310303222101 |
5 | 11430122434112440 |
6 | 241014412151013 |
7 | 21156054262146 |
oct | 3045764635221 |
9 | 665253000770 |
10 | 211255769745 |
11 | 81658413649 |
12 | 34b39168469 |
13 | 16bc9229467 |
14 | a320d303cd |
15 | 57666d7230 |
hex | 312fd33a91 |
211255769745 has 48 divisors (see below), whose sum is σ = 388478909520. Its totient is φ = 105833582592.
The previous prime is 211255769723. The next prime is 211255769759. The reversal of 211255769745 is 547967552112.
211255769745 is a `hidden beast` number, since 2 + 1 + 1 + 25 + 576 + 9 + 7 + 45 = 666.
It can be written as a sum of positive squares in 8 ways, for example, as 67217303169 + 144038466576 = 259263^2 + 379524^2 .
It is not a de Polignac number, because 211255769745 - 27 = 211255769617 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 211255769691 and 211255769700.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 118117 + ... + 660653.
It is an arithmetic number, because the mean of its divisors is an integer number (8093310615).
Almost surely, 2211255769745 is an apocalyptic number.
It is an amenable number.
211255769745 is a deficient number, since it is larger than the sum of its proper divisors (177223139775).
211255769745 is a wasteful number, since it uses less digits than its factorization.
211255769745 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 543074 (or 543071 counting only the distinct ones).
The product of its digits is 5292000, while the sum is 54.
The spelling of 211255769745 in words is "two hundred eleven billion, two hundred fifty-five million, seven hundred sixty-nine thousand, seven hundred forty-five".
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