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211261345753 is a prime number
BaseRepresentation
bin1100010011000000101…
…0000100111111011001
3202012022011111022201011
43010300022010333121
511430130401031003
6241015131453521
721156152544553
oct3046012047731
9665264438634
10211261345753
1181660581a17
1234b3abb72a1
1316bca42c483
14a3219824d3
155766e3946d
hex3130284fd9

211261345753 has 2 divisors, whose sum is σ = 211261345754. Its totient is φ = 211261345752.

The previous prime is 211261345733. The next prime is 211261345787. The reversal of 211261345753 is 357543162112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 184927521024 + 26333824729 = 430032^2 + 162277^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-211261345753 is a prime.

It is a super-2 number, since 2×2112613457532 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211261345733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105630672876 + 105630672877.

It is an arithmetic number, because the mean of its divisors is an integer number (105630672877).

Almost surely, 2211261345753 is an apocalyptic number.

It is an amenable number.

211261345753 is a deficient number, since it is larger than the sum of its proper divisors (1).

211261345753 is an equidigital number, since it uses as much as digits as its factorization.

211261345753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 151200, while the sum is 40.

The spelling of 211261345753 in words is "two hundred eleven billion, two hundred sixty-one million, three hundred forty-five thousand, seven hundred fifty-three".