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21130041042103 = 73018577291729
BaseRepresentation
bin1001100110111101110001…
…00101110010010010110111
32202211000022220001022221111
410303132320211302102313
510232143311001321403
6112535001251255451
74310411054263360
oct463367045622267
982730286038844
1021130041042103
116807222344654
122453187baa587
13ba3728ac4066
145309b13b4b67
15269992d6b56d
hex1337b89724b7

21130041042103 has 4 divisors (see below), whose sum is σ = 24148618333840. Its totient is φ = 18111463750368.

The previous prime is 21130041042079. The next prime is 21130041042107. The reversal of 21130041042103 is 30124014003112.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21130041042103 - 225 = 21130007487671 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21130041042107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1509288645858 + ... + 1509288645871.

It is an arithmetic number, because the mean of its divisors is an integer number (6037154583460).

Almost surely, 221130041042103 is an apocalyptic number.

21130041042103 is a deficient number, since it is larger than the sum of its proper divisors (3018577291737).

21130041042103 is an equidigital number, since it uses as much as digits as its factorization.

21130041042103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3018577291736.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 21130041042103 its reverse (30124014003112), we get a palindrome (51254055045215).

The spelling of 21130041042103 in words is "twenty-one trillion, one hundred thirty billion, forty-one million, forty-two thousand, one hundred three".

Divisors: 1 7 3018577291729 21130041042103