Base | Representation |
---|---|
bin | 1001100110111101110001… |
… | …00101110010010010111000 |
3 | 2202211000022220001022221112 |
4 | 10303132320211302102320 |
5 | 10232143311001321404 |
6 | 112535001251255452 |
7 | 4310411054263361 |
oct | 463367045622270 |
9 | 82730286038845 |
10 | 21130041042104 |
11 | 6807222344655 |
12 | 2453187baa588 |
13 | ba3728ac4067 |
14 | 5309b13b4b68 |
15 | 269992d6b56e |
hex | 1337b89724b8 |
21130041042104 has 64 divisors (see below), whose sum is σ = 42025445913600. Its totient is φ = 9925515800064.
The previous prime is 21130041042079. The next prime is 21130041042107. The reversal of 21130041042104 is 40124014003112.
It is a self number, because there is not a number n which added to its sum of digits gives 21130041042104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21130041042107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 597906467 + ... + 597941805.
It is an arithmetic number, because the mean of its divisors is an integer number (656647592400).
Almost surely, 221130041042104 is an apocalyptic number.
It is an amenable number.
21130041042104 is a deficient number, since it is larger than the sum of its proper divisors (20895404871496).
21130041042104 is a wasteful number, since it uses less digits than its factorization.
21130041042104 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43212 (or 43208 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 21130041042104 its reverse (40124014003112), we get a palindrome (61254055045216).
The spelling of 21130041042104 in words is "twenty-one trillion, one hundred thirty billion, forty-one million, forty-two thousand, one hundred four".
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