Base | Representation |
---|---|
bin | 10011101011011100… |
… | …110000101010100000 |
3 | 2000112120220222022212 |
4 | 103223130300222200 |
5 | 321233243214204 |
6 | 13412414221252 |
7 | 1345423332602 |
oct | 235334605240 |
9 | 60476828285 |
10 | 21130054304 |
11 | 8a634015a7 |
12 | 41184b4828 |
13 | 1cb984c218 |
14 | 1046409172 |
15 | 83a08bc6e |
hex | 4eb730aa0 |
21130054304 has 12 divisors (see below), whose sum is σ = 41599794474. Its totient is φ = 10565027136.
The previous prime is 21130054289. The next prime is 21130054357. The reversal of 21130054304 is 40345003112.
It can be written as a sum of positive squares in only one way, i.e., 14435541904 + 6694512400 = 120148^2 + 81820^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 21130054304.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330157067 + ... + 330157130.
Almost surely, 221130054304 is an apocalyptic number.
It is an amenable number.
21130054304 is a deficient number, since it is larger than the sum of its proper divisors (20469740170).
21130054304 is an equidigital number, since it uses as much as digits as its factorization.
21130054304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 660314207 (or 660314199 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 21130054304 its reverse (40345003112), we get a palindrome (61475057416).
The spelling of 21130054304 in words is "twenty-one billion, one hundred thirty million, fifty-four thousand, three hundred four".
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