Base | Representation |
---|---|
bin | 11110101111111001001… |
… | …101101011000000000011 |
3 | 21111000001022012100222011 |
4 | 132233321031223000003 |
5 | 234104421033144443 |
6 | 4254411534353351 |
7 | 305442234051424 |
oct | 36577115530003 |
9 | 7430038170864 |
10 | 2113010053123 |
11 | 7451390a8402 |
12 | 2a162295b857 |
13 | 1243435555a8 |
14 | 743ad73564b |
15 | 39e6e4a2b9d |
hex | 1ebf936b003 |
2113010053123 has 2 divisors, whose sum is σ = 2113010053124. Its totient is φ = 2113010053122.
The previous prime is 2113010053117. The next prime is 2113010053159. The reversal of 2113010053123 is 3213500103112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2113010053123 is a prime.
It is a super-2 number, since 2×21130100531232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2113010053094 and 2113010053103.
It is not a weakly prime, because it can be changed into another prime (2113010053423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056505026561 + 1056505026562.
It is an arithmetic number, because the mean of its divisors is an integer number (1056505026562).
Almost surely, 22113010053123 is an apocalyptic number.
2113010053123 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113010053123 is an equidigital number, since it uses as much as digits as its factorization.
2113010053123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 540, while the sum is 22.
Adding to 2113010053123 its reverse (3213500103112), we get a palindrome (5326510156235).
The spelling of 2113010053123 in words is "two trillion, one hundred thirteen billion, ten million, fifty-three thousand, one hundred twenty-three".
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