Base | Representation |
---|---|
bin | 11110101111111001001… |
… | …101101011000010000011 |
3 | 21111000001022012101010220 |
4 | 132233321031223002003 |
5 | 234104421033201001 |
6 | 4254411534354123 |
7 | 305442234051666 |
oct | 36577115530203 |
9 | 7430038171126 |
10 | 2113010053251 |
11 | 7451390a8509 |
12 | 2a162295b943 |
13 | 124343555676 |
14 | 743ad7356dd |
15 | 39e6e4a2c36 |
hex | 1ebf936b083 |
2113010053251 has 16 divisors (see below), whose sum is σ = 2918154624000. Its totient is φ = 1358579604960.
The previous prime is 2113010053213. The next prime is 2113010053277. The reversal of 2113010053251 is 1523500103112.
It is not a de Polignac number, because 2113010053251 - 27 = 2113010053123 is a prime.
It is a super-2 number, since 2×21130100532512 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2113010053201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38745001 + ... + 38799498.
It is an arithmetic number, because the mean of its divisors is an integer number (182384664000).
Almost surely, 22113010053251 is an apocalyptic number.
2113010053251 is a deficient number, since it is larger than the sum of its proper divisors (805144570749).
2113010053251 is a wasteful number, since it uses less digits than its factorization.
2113010053251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77544826.
The product of its (nonzero) digits is 900, while the sum is 24.
Adding to 2113010053251 its reverse (1523500103112), we get a palindrome (3636510156363).
The spelling of 2113010053251 in words is "two trillion, one hundred thirteen billion, ten million, fifty-three thousand, two hundred fifty-one".
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