Base | Representation |
---|---|
bin | 10011101011011101… |
… | …000101100101111111 |
3 | 2000112121002022220221 |
4 | 103223131011211333 |
5 | 321233303440111 |
6 | 13412420122211 |
7 | 1345424140540 |
oct | 235335054577 |
9 | 60477068827 |
10 | 21130140031 |
11 | 8a6345aa50 |
12 | 4118536367 |
13 | 1cb987c250 |
14 | 104642c4c7 |
15 | 83a0a7371 |
hex | 4eb74597f |
21130140031 has 32 divisors (see below), whose sum is σ = 28397311488. Its totient is φ = 15184160640.
The previous prime is 21130139999. The next prime is 21130140041. The reversal of 21130140031 is 13004103112.
It is not a de Polignac number, because 21130140031 - 25 = 21130139999 is a prime.
It is a super-3 number, since 3×211301400313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 21130139987 and 21130140014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21130140041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1114725 + ... + 1133521.
It is an arithmetic number, because the mean of its divisors is an integer number (887415984).
Almost surely, 221130140031 is an apocalyptic number.
21130140031 is a deficient number, since it is larger than the sum of its proper divisors (7267171457).
21130140031 is a wasteful number, since it uses less digits than its factorization.
21130140031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19951.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 21130140031 its reverse (13004103112), we get a palindrome (34134243143).
It can be divided in two parts, 21130 and 140031, that added together give a palindrome (161161).
The spelling of 21130140031 in words is "twenty-one billion, one hundred thirty million, one hundred forty thousand, thirty-one".
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