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2113032131341 = 19111212217439
BaseRepresentation
bin11110101111111010100…
…001111001001100001101
321111000002211202001120221
4132233322201321030031
5234104442211200331
64254414043511341
7305442622524415
oct36577241711415
97430084661527
102113032131341
1174514a60806a
122a162a228551
13124347cb5921
14743b2641645
1539e713b4711
hex1ebfa87930d

2113032131341 has 4 divisors (see below), whose sum is σ = 2224244348800. Its totient is φ = 2001819913884.

The previous prime is 2113032131321. The next prime is 2113032131381. The reversal of 2113032131341 is 1431312303112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2113032131341 - 223 = 2113023742733 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113032131321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55606108701 + ... + 55606108738.

It is an arithmetic number, because the mean of its divisors is an integer number (556061087200).

Almost surely, 22113032131341 is an apocalyptic number.

It is an amenable number.

2113032131341 is a deficient number, since it is larger than the sum of its proper divisors (111212217459).

2113032131341 is a wasteful number, since it uses less digits than its factorization.

2113032131341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 111212217458.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 2113032131341 its reverse (1431312303112), we get a palindrome (3544344434453).

The spelling of 2113032131341 in words is "two trillion, one hundred thirteen billion, thirty-two million, one hundred thirty-one thousand, three hundred forty-one".

Divisors: 1 19 111212217439 2113032131341