Base | Representation |
---|---|
bin | 10011101011011101… |
… | …111010010110111001 |
3 | 2000112121111022101110 |
4 | 103223131322112321 |
5 | 321233332344103 |
6 | 13412424510533 |
7 | 1345426030614 |
oct | 235335722671 |
9 | 60477438343 |
10 | 21130356153 |
11 | 8a63598365 |
12 | 411861b449 |
13 | 1cb992672a |
14 | 104648717b |
15 | 83a0eb403 |
hex | 4eb77a5b9 |
21130356153 has 4 divisors (see below), whose sum is σ = 28173808208. Its totient is φ = 14086904100.
The previous prime is 21130356113. The next prime is 21130356161. The reversal of 21130356153 is 35165303112.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 21130356153 - 26 = 21130356089 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 21130356153.
It is not an unprimeable number, because it can be changed into a prime (21130356113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3521726023 + ... + 3521726028.
It is an arithmetic number, because the mean of its divisors is an integer number (7043452052).
Almost surely, 221130356153 is an apocalyptic number.
It is an amenable number.
21130356153 is a deficient number, since it is larger than the sum of its proper divisors (7043452055).
21130356153 is an equidigital number, since it uses as much as digits as its factorization.
21130356153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7043452054.
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 21130356153 its reverse (35165303112), we get a palindrome (56295659265).
The spelling of 21130356153 in words is "twenty-one billion, one hundred thirty million, three hundred fifty-six thousand, one hundred fifty-three".
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