Base | Representation |
---|---|
bin | 1001100110111111100100… |
… | …11110001100110100100101 |
3 | 2202211002211120022211000220 |
4 | 10303133302132030310211 |
5 | 10232202303101212013 |
6 | 112535241501154553 |
7 | 4310444115355551 |
oct | 463376236146445 |
9 | 82732746284026 |
10 | 21131012132133 |
11 | 68076805119a2 |
12 | 24533b925ba59 |
13 | ba385204b447 |
14 | 530a64358861 |
15 | 2699ed23bb23 |
hex | 1337f278cd25 |
21131012132133 has 16 divisors (see below), whose sum is σ = 28674392090496. Its totient is φ = 13838096946240.
The previous prime is 21131012132107. The next prime is 21131012132141. The reversal of 21131012132133 is 33123121013112.
It is not a de Polignac number, because 21131012132133 - 210 = 21131012131109 is a prime.
It is a super-2 number, since 2×211310121321332 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21131012172133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 76129641 + ... + 76406702.
It is an arithmetic number, because the mean of its divisors is an integer number (1792149505656).
Almost surely, 221131012132133 is an apocalyptic number.
It is an amenable number.
21131012132133 is a deficient number, since it is larger than the sum of its proper divisors (7543379958363).
21131012132133 is a wasteful number, since it uses less digits than its factorization.
21131012132133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 152537164.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 21131012132133 its reverse (33123121013112), we get a palindrome (54254133145245).
The spelling of 21131012132133 in words is "twenty-one trillion, one hundred thirty-one billion, twelve million, one hundred thirty-two thousand, one hundred thirty-three".
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