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2113113014301 = 37122129448313
BaseRepresentation
bin11110101111111111010…
…110011100000000011101
321111000022110221100011010
4132233333112130000131
5234110123412424201
64254430053245433
7305444624155662
oct36577726340035
97430273840133
102113113014301
11745191231693
122a1651333879
1312435b994b73
14743bd297a69
1539e7853ebd6
hex1ebff59c01d

2113113014301 has 16 divisors (see below), whose sum is σ = 2857302380160. Its totient is φ = 1388834711040.

The previous prime is 2113113014279. The next prime is 2113113014317. The reversal of 2113113014301 is 1034103113112.

It is not a de Polignac number, because 2113113014301 - 211 = 2113113012253 is a prime.

It is a super-2 number, since 2×21131130143012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2113113013301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4489321 + ... + 4937633.

It is an arithmetic number, because the mean of its divisors is an integer number (178581398760).

Almost surely, 22113113014301 is an apocalyptic number.

It is an amenable number.

2113113014301 is a deficient number, since it is larger than the sum of its proper divisors (744189365859).

2113113014301 is a wasteful number, since it uses less digits than its factorization.

2113113014301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 470516.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2113113014301 its reverse (1034103113112), we get a palindrome (3147216127413).

The spelling of 2113113014301 in words is "two trillion, one hundred thirteen billion, one hundred thirteen million, fourteen thousand, three hundred one".

Divisors: 1 3 71 213 22129 66387 448313 1344939 1571159 4713477 31830223 95490669 9920718377 29762155131 704371004767 2113113014301