Base | Representation |
---|---|
bin | 11110101111111111010… |
… | …110011100000000101101 |
3 | 21111000022110221100011201 |
4 | 132233333112130000231 |
5 | 234110123412424232 |
6 | 4254430053245501 |
7 | 305444624156014 |
oct | 36577726340055 |
9 | 7430273840151 |
10 | 2113113014317 |
11 | 7451912316a8 |
12 | 2a1651333891 |
13 | 12435b994b86 |
14 | 743bd297a7b |
15 | 39e7853ebe7 |
hex | 1ebff59c02d |
2113113014317 has 2 divisors, whose sum is σ = 2113113014318. Its totient is φ = 2113113014316.
The previous prime is 2113113014279. The next prime is 2113113014407. The reversal of 2113113014317 is 7134103113112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1882894418596 + 230218595721 = 1372186^2 + 479811^2 .
It is a cyclic number.
It is not a de Polignac number, because 2113113014317 - 227 = 2112978796589 is a prime.
It is a super-2 number, since 2×21131130143172 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2113113014717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056556507158 + 1056556507159.
It is an arithmetic number, because the mean of its divisors is an integer number (1056556507159).
Almost surely, 22113113014317 is an apocalyptic number.
It is an amenable number.
2113113014317 is a deficient number, since it is larger than the sum of its proper divisors (1).
2113113014317 is an equidigital number, since it uses as much as digits as its factorization.
2113113014317 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 28.
Adding to 2113113014317 its reverse (7134103113112), we get a palindrome (9247216127429).
The spelling of 2113113014317 in words is "two trillion, one hundred thirteen billion, one hundred thirteen million, fourteen thousand, three hundred seventeen".
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